Match
`{:("Column I","Column II"),((A)O_3+H_2O_2 " "to,(p)"Blue"),((B)O_3+"starch KI"" " to,(q)"Tailing" ),(( C)O_3+Hg" " to,(r)HIO_3),((D)O_3+I_2+H_2O" "to,(s)O_2+H_2O):}`

Explanation

To solve the matching question, we will analyze each reaction involving ozone (O₃) and determine the corresponding outcomes from Column II.

### Step-by-Step Solution:

1. **Reaction A: O₃ + H₂O₂**
- When ozone reacts with hydrogen peroxide, it produces water (H₂O) and oxygen (O₂).
- **Result:** O₃ + H₂O₂ → H₂O + 2O₂
- **Match:** (A) → (s) O₂ + H₂O

2. **Reaction B: O₃ + Starch KI**
- Ozone reacts with potassium iodide (KI) in the presence of starch, resulting in the formation of iodine (I₂) which turns the starch blue.
- **Result:** O₃ + 2KI + H₂O → 2KOH + I₂ + O₂
- **Match:** (B) → (p) Blue

3. **Reaction C: O₃ + Hg**
- The reaction of ozone with mercury leads to the formation of mercurous oxide (Hg₂O) and oxygen. This reaction is characterized by the "tailing" phenomenon where the mercury sticks to the glass.
- **Result:** O₃ + 2Hg → Hg₂O + O₂
- **Match:** (C) → (q) Tailing

4. **Reaction D: O₃ + I₂ + H₂O**
- Ozone oxidizes iodine in the presence of water to form iodic acid (HIO₃) and oxygen.
- **Result:** O₃ + I₂ + H₂O → 2HIO₃ + 5O₂
- **Match:** (D) → (r) HIO₃

### Final Matches:
- (A) → (s) O₂ + H₂O
- (B) → (p) Blue
- (C) → (q) Tailing
- (D) → (r) HIO₃

### Summary of Matches:
- A → s
- B → p
- C → q
- D → r