Chlorine reacts with dilute NaOH under ordinary conditions to give

Options

A. NaCl and `NaClO_(3)`
B. (b) NaCl and `ClO_(2)`
C. (c) NaCl and NaClO
D. (d) NaCl and `Cl_(2)O`

Explanation

To solve the question regarding the reaction of chlorine with dilute NaOH, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chlorine (Cl₂) and dilute sodium hydroxide (NaOH).

### Step 2: Understand the Conditions
The question specifies that the reaction occurs under ordinary conditions, which implies that we are dealing with dilute and cold NaOH.

### Step 3: Write the Reaction
When chlorine reacts with dilute NaOH, the products formed are sodium chloride (NaCl) and sodium hypochlorite (NaClO), along with water (H₂O). The balanced chemical equation for this reaction is:

\[ \text{Cl}_2 + 2 \text{NaOH} \rightarrow \text{NaCl} + \text{NaClO} + \text{H}_2\text{O} \]

### Step 4: Analyze the Products
From the balanced equation, we can see that the products of the reaction are:
- Sodium chloride (NaCl)
- Sodium hypochlorite (NaClO)
- Water (H₂O)

### Step 5: Check the Options
Now, we need to check which of the given options matches the products formed:
1. NaCl and NaClO3
2. NaCl and NaClO2
3. NaCl and NaClO
4. NaCl and Cl2O

From our reaction, we see that the correct products are NaCl and NaClO, which corresponds to option 3.

### Conclusion
The correct answer is:
**NaCl and NaClO (Option C)**.

---