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Excess of KI reacts with CuSO(4) solutio...

Excess of `KI` reacts with `CuSO_(4)` solution and `Na_(2)SO_(3)` solution is added to it. Which of the following statements in incorrect for the reaction?

A

Evolved `I_2` is reduced

B

`CuI_2` is formed

C

`Na_2S_2O_3` is oxidised

D

`Cu_2I_2` is formed

Text Solution

Verified by Experts

The correct Answer is:
B
`2CuSO_4+4KIto2K_2SO_4+Cu_2l_2+l_2`
`2Na_2S_2O_3+I_2to Na_2S_4O_6+2Nal , Cu l_2` is not formed according to following reaction .
`2Cu l_2`(unstable)`toCu_2l_2+l_2`
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