Which of the following products is formed by the reaction of manganese (II) ions salt with peroxodisulphate `(S_2O_6^(2-))`?

Options

A. `Mn_2O_7`
B. `Mn_3O_4`
C. `MnO_4^(2-)`
D. `MnO^(-)`

Explanation

To determine the product formed by the reaction of manganese (II) ions with peroxodisulfate (S₂O₈²⁻), we can follow these steps:

### Step 1: Identify the Reactants
- The reactants in this reaction are manganese (II) ions (Mn²⁺) and peroxodisulfate ions (S₂O₈²⁻).

### Step 2: Determine the Oxidation States
- In manganese (II) ions, manganese has an oxidation state of +2.
- In peroxodisulfate (S₂O₈²⁻), the sulfur atoms are in a +6 oxidation state, and the peroxodisulfate ion can act as a strong oxidizing agent.

### Step 3: Predict the Oxidation Reaction
- Since Mn²⁺ is being oxidized, it will lose electrons and increase its oxidation state. The Mn²⁺ will be oxidized to Mn⁷⁺, which is found in permanganate ions (MnO₄⁻).

### Step 4: Write the Balanced Reaction
- The balanced reaction can be represented as follows:
\[ 2 \text{Mn}^{2+} + 5 \text{S}_2\text{O}_8^{2-} + 16 \text{H}^+ \rightarrow 2 \text{MnO}_4^{-} + 10 \text{SO}_4^{2-} + 8 \text{H}_2\text{O} \]
- Here, manganese is oxidized from +2 to +7, and sulfate ions (SO₄²⁻) and protons (H⁺) are produced as byproducts.

### Step 5: Identify the Main Product
- The main product of this reaction is the permanganate ion (MnO₄⁻).

### Conclusion
- Therefore, the product formed by the reaction of manganese (II) ions with peroxodisulfate is **MnO₄⁻**.

### Final Answer
- The correct answer is **MnO₄⁻**.

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