Which of the following products are formed when potassium
bromide reacts with potassium permangnate in alkaline `pH`?

Options

A. `BrO_3^(-), MnO_2`
B. `BrO_4^(-), Mn^(2+)`
C. `Br_2, MnO_2`
D. `BrO^(-), MnO_4^(2-)`

Explanation

To determine the products formed when potassium bromide (KBr) reacts with potassium permanganate (KMnO4) in an alkaline medium, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are potassium bromide (KBr) and potassium permanganate (KMnO4) in an alkaline medium (basic pH).

2. **Write the Balanced Reaction**:
- In an alkaline medium, potassium permanganate acts as an oxidizing agent. The balanced reaction can be written as:
\[ 2 \text{KMnO}_4 + 6 \text{KBr} + 6 \text{OH}^- \rightarrow 2 \text{MnO}_2 + 3 \text{KBrO}_3 + 6 \text{KOH} + 3 \text{H}_2\text{O} \]

3. **Identify the Products**:
- From the balanced equation, the products formed are:
- Manganese dioxide (MnO2)
- Potassium bromate (KBrO3)
- Potassium hydroxide (KOH)
- Water (H2O)

4. **Summarize the Key Products**:
- The main products of the reaction are:
- MnO2
- KBrO3

5. **Conclusion**:
- Therefore, when potassium bromide reacts with potassium permanganate in an alkaline medium, the products formed are manganese dioxide (MnO2) and potassium bromate (KBrO3).