Statement-1:Dipositive zinc exhibits diamagnetism due to loss of
two electrons from 3d-orbital of neutral atom.
Statement-2:The electronic configuration of zinc (Z=30) is `[Ar]^(18)3d^10 4s^2`

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is
NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the question, we need to analyze both statements regarding zinc (Zn) and its dipositive form (Zn²⁺).

### Step-by-Step Solution:

1. **Identify the Atomic Number and Electronic Configuration of Zinc:**
- Zinc has an atomic number of 30.
- The electronic configuration of neutral zinc can be written as:
\[ \text{Zn: } [\text{Ar}] 3d^{10} 4s^2 \]
- Here, [Ar] represents the electron configuration of Argon, which accounts for the first 18 electrons.

2. **Determine the Electronic Configuration of Zn²⁺:**
- When zinc loses two electrons to form Zn²⁺, the electrons are removed from the outermost shell first, which is the 4s orbital.
- Therefore, the electronic configuration of Zn²⁺ is:
\[ \text{Zn}^{2+}: [\text{Ar}] 3d^{10} \]
- This indicates that the 4s electrons are lost, and the 3d electrons remain fully paired.

3. **Analyze Statement 1:**
- Statement 1 claims that dipositive zinc exhibits diamagnetism due to the loss of two electrons from the 3d orbital.
- This statement is **incorrect** because the electrons are actually lost from the 4s orbital, not the 3d orbital.

4. **Analyze Statement 2:**
- Statement 2 states that the electronic configuration of zinc (Z=30) is \([Ar] 3d^{10} 4s^2\).
- This statement is **correct** as it accurately describes the electronic configuration of neutral zinc.

5. **Conclusion:**
- Based on the analysis, we conclude that:
- Statement 1 is **false**.
- Statement 2 is **true**.

### Final Answer:
- **Statement 1 is false, Statement 2 is true.**