How many moles of methyl alcohol is obtained when 1 mole of hydrated ferric chloride (i.e. `FeCl_3 . 6H_2O)` is made anhydrous by reacting with 6 moles of 2,2 dimethoxypropane.

Explanation

To solve the problem of how many moles of methyl alcohol (CH₃OH) are obtained when 1 mole of hydrated ferric chloride (FeCl₃·6H₂O) is made anhydrous by reacting with 6 moles of 2,2-dimethoxypropane, we can follow these steps:

### Step 1: Understand the Reaction
We start with 1 mole of hydrated ferric chloride (FeCl₃·6H₂O) and react it with 6 moles of 2,2-dimethoxypropane. The goal is to determine how many moles of methyl alcohol (CH₃OH) are produced in this reaction.

### Step 2: Identify the Components
- **Hydrated Ferric Chloride**: FeCl₃·6H₂O
- **2,2-Dimethoxypropane**: This compound contains methoxy groups (OCH₃), which can release methyl alcohol upon reaction.

### Step 3: Write the Reaction
The reaction can be represented as:
\[ \text{FeCl}_3 \cdot 6\text{H}_2\text{O} + 6 \text{(CH}_3\text{O)}_2\text{C(CH}_3\text{)}_2 \rightarrow \text{FeCl}_3 + 12 \text{CH}_3\text{OH} \]

### Step 4: Determine Moles of Methyl Alcohol
From the balanced equation, we see that for every 1 mole of FeCl₃·6H₂O reacted, we produce 12 moles of methyl alcohol (CH₃OH).

### Conclusion
Thus, when 1 mole of hydrated ferric chloride is made anhydrous by reacting with 6 moles of 2,2-dimethoxypropane, **12 moles of methyl alcohol are obtained**.

### Final Answer
**12 moles of methyl alcohol (CH₃OH)** are obtained.

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