Consider the following statements and arrange in the order of true/false as given in the codes.
`S_1`:Like `CO_3^(2-),SO_3^(2-)` ions also give test with baryle water , `Ba(OH)_2`.
`S_2`:`Ag_2SO_3` is insoluble in dilute `HNO_3`
`S_3`:Triodide ions `(l_3^(-))` produced by the reaction of `Cu^(2+)` and Kl solution are not reduced by excess of sodium thiosulphate solution.
`S_4`:Black precipitate of `Cu(SCN)_2` turns into white precipitate when it reacts with saturated solution of `SO_2` in water.

Options

A. F T T F
B. T F F T
C. F T F T
D. T T F T

Explanation

To solve the question, we need to evaluate each statement one by one and determine whether they are true or false.

### Step 1: Evaluate Statement S1
**Statement S1**: Like \( \text{CO}_3^{2-}, \text{SO}_3^{2-} \) ions also give a test with baryte water, \( \text{Ba(OH)}_2 \).

- **Analysis**: The carbonate ion \( \text{CO}_3^{2-} \) reacts with barium hydroxide to form a precipitate of barium carbonate. Similarly, the sulfite ion \( \text{SO}_3^{2-} \) can also react with barium hydroxide to form barium sulfite, which is also a precipitate.
- **Conclusion**: This statement is **True**.

### Step 2: Evaluate Statement S2
**Statement S2**: \( \text{Ag}_2\text{SO}_3 \) is insoluble in dilute \( \text{HNO}_3 \).

- **Analysis**: Silver sulfite \( \text{Ag}_2\text{SO}_3 \) is actually soluble in dilute nitric acid. When it dissolves, it forms silver nitrate and sulfurous acid.
- **Conclusion**: This statement is **False**.

### Step 3: Evaluate Statement S3
**Statement S3**: Triiodide ions \( \text{I}_3^{-} \) produced by the reaction of \( \text{Cu}^{2+} \) and KI solution are not reduced by excess sodium thiosulphate solution.

- **Analysis**: When \( \text{Cu}^{2+} \) reacts with \( \text{I}^- \), it forms \( \text{Cu}^{+} \) and \( \text{I}_2 \). The \( \text{I}_2 \) can be reduced by sodium thiosulphate, which means that the statement is incorrect as the triiodide ions can indeed be reduced.
- **Conclusion**: This statement is **False**.

### Step 4: Evaluate Statement S4
**Statement S4**: Black precipitate of \( \text{Cu(SCN)}_2 \) turns into a white precipitate when it reacts with saturated solution of \( \text{SO}_2 \) in water.

- **Analysis**: The black precipitate of copper(I) thiocyanate \( \text{Cu(SCN)}_2 \) can indeed react with sulfur dioxide, resulting in a white precipitate of \( \text{Cu}_2\text{SO}_4 \) or other copper sulfite compounds.
- **Conclusion**: This statement is **True**.

### Final Arrangement of Statements
Now, we can summarize the truth values of the statements:
- **S1**: True
- **S2**: False
- **S3**: False
- **S4**: True

Thus, the order of true/false statements is: **True, False, False, True**.

### Answer Code
The correct code for the statements is **T, F, F, T**, which corresponds to **Option 2**.

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