Consider the following statements and arrange in the order of true/false as given in the codes.
`S_1`:The addition of chlorine water drop wise to a solution of a bromide liberate free bromine, which colours the solution orange red.
`S_2`:Chlorine gas bleaches the filter paper moistened with yellow dyestuff, fluorescein.
`S_3`:Nitrogen gas is evolved when a solution of nitrate is boiled with zinc dust and sodium hydroxide solution.

Options

A. T T T
B. T F T
C. T F F
D. T T F

Explanation

To solve the question, we need to evaluate each statement and determine if they are true or false.

### Step 1: Analyze Statement S1
**Statement S1**: The addition of chlorine water dropwise to a solution of bromide liberates free bromine, which colors the solution orange-red.

- When chlorine water (Cl2 in water) is added to a bromide solution (Br-), a reaction occurs where bromide ions are oxidized to bromine (Br2).
- The liberated bromine (Br2) imparts an orange-red color to the solution.

**Conclusion**: S1 is **True**.

### Step 2: Analyze Statement S2
**Statement S2**: Chlorine gas bleaches the filter paper moistened with yellow dyestuff, fluorescein.

- Chlorine gas reacts with water to form hypochlorous acid (HClO), which can further dissociate to produce nascent oxygen.
- This nascent oxygen is a strong bleaching agent and can bleach dyes, including fluorescein, which is yellow in color.

**Conclusion**: S2 is **True**.

### Step 3: Analyze Statement S3
**Statement S3**: Nitrogen gas is evolved when a solution of nitrate is boiled with zinc dust and sodium hydroxide solution.

- When a nitrate (NO3-) is treated with zinc dust and sodium hydroxide, the reaction produces ammonia (NH3) rather than nitrogen gas (N2).
- Therefore, the statement claiming that nitrogen gas is evolved is incorrect.

**Conclusion**: S3 is **False**.

### Final Arrangement
Based on the evaluations:
- S1: True
- S2: True
- S3: False

Thus, the order of true/false for the statements is: **True, True, False**.

### Answer Code
The correct answer code is **T, T, F**.

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