Which of the following is/are correctly matched ?

Options

A. `[Al(OH)_4]^(-)(aq)+NH_4^(+)(aq)overset("Slightly heat")to` White precipitate and liberation of ammonia
B. `Pb^(2+)(aq)+2Br^(-)(aq)to`red precipitate
C. `BiI_3`(black precipitate)+`H_2O(l)overset(Delta)`Orange precipitate
D. `Cu^(2+)(aq)+K_4[Fe(CN)_6](aq)to` White precipitate

Explanation

To determine which of the given reactions and their corresponding precipitate colors are correctly matched, we will analyze each statement one by one.

### Step-by-Step Solution:

1. **First Reaction:**
- **Reaction:** Al(OH)₄⁻ + NH₄⁺ (upon slight heating)
- **Expected Products:** Al(OH)₃ + NH₃ + H₂O
- **Observation:** The reaction produces a white precipitate of Al(OH)₃ and liberates ammonia gas (NH₃).
- **Conclusion:** This statement is **correct**.

2. **Second Reaction:**
- **Reaction:** Pb²⁺ + 2 Br⁻
- **Expected Products:** PbBr₂
- **Observation:** The color of PbBr₂ is a white precipitate, not red.
- **Conclusion:** This statement is **incorrect** (it claims red precipitate).

3. **Third Reaction:**
- **Reaction:** BiI₃ + H₂O
- **Expected Products:** BiOI + 2 HI
- **Observation:** The reaction produces an orange precipitate of BiOI.
- **Conclusion:** This statement is **correct**.

4. **Fourth Reaction:**
- **Reaction:** Cu²⁺ + K₄[Fe(CN)₆]
- **Expected Products:** Cu₂[Fe(CN)₆]
- **Observation:** The precipitate formed is chocolate brown, not white.
- **Conclusion:** This statement is **incorrect** (it claims white precipitate).

### Final Conclusion:
The correctly matched statements are:
- **Statement 1:** Correct (White precipitate of Al(OH)₃ and liberation of NH₃)
- **Statement 3:** Correct (Orange precipitate of BiOI)

Thus, the correct options are **1 and 3**.