When ethyl bromide is heated with sodium in dry ether solvent, the alkane obtained is:

Options

A. ethane
B. propane
C. butane
D. None

Explanation

To solve the question, we need to understand the reaction that occurs when ethyl bromide is heated with sodium in dry ether. This reaction is a classic example of the Wurtz reaction, which is used to couple alkyl halides to form higher alkanes.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is ethyl bromide, which has the chemical formula C2H5Br.

2. **Understand the Reaction Conditions**:
- The reaction is carried out in the presence of sodium (Na) and dry ether. Sodium acts as a reducing agent in this reaction.

3. **Write the Reaction**:
- When ethyl bromide (C2H5Br) is treated with sodium in dry ether, the sodium will react with two molecules of ethyl bromide to form a new alkane. The general reaction can be represented as:
\[ 2 \, \text{C}_2\text{H}_5\text{Br} + 2 \, \text{Na} \rightarrow \text{C}_4\text{H}_{10} + 2 \, \text{NaBr} \]
- Here, two ethyl groups (C2H5) combine to form butane (C4H10) and sodium bromide (NaBr).

4. **Identify the Product**:
- The product formed from this reaction is butane (C4H10).

5. **Conclusion**:
- Therefore, the alkane obtained when ethyl bromide is heated with sodium in dry ether solvent is butane.

### Final Answer:
The alkane obtained is **butane**.