Statement-1:When 3-Chlorobut-1-ene react `H_2O` then give four products.
Statement-2:Intermediate is carbocation and it show resonance and recemisation.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the question regarding the reaction of 3-Chlorobut-1-ene with water and the resulting products, we can break down the problem step by step.

### Step-by-Step Solution:

1. **Identify the Structure of 3-Chlorobut-1-ene:**
- The structure of 3-Chlorobut-1-ene can be drawn as follows:
```
CH2=CH-CH(Cl)-CH3
```
- Here, the double bond is between the first and second carbon atoms, and the chlorine atom is attached to the third carbon.

2. **Reaction with Water:**
- When 3-Chlorobut-1-ene reacts with water (in the presence of an acid, H⁺), a nucleophilic substitution reaction occurs.
- The chlorine atom (Cl) is a good leaving group and will leave, forming a carbocation intermediate.

3. **Formation of Carbocation:**
- The carbocation formed after the departure of Cl is:
```
CH2=CH-CH⁺-CH3
```
- This carbocation is a secondary carbocation and is stabilized by resonance with the double bond.

4. **Resonance Stabilization:**
- The carbocation can undergo resonance, which allows for the delocalization of the positive charge:
```
CH2=CH-CH⁺-CH3 ↔ CH3-CH⁺-CH=CH2
```
- This resonance leads to different structural forms of the carbocation.

5. **Nucleophilic Attack:**
- The water molecule (acting as a nucleophile) can attack the carbocation, leading to the formation of alcohols.
- Depending on the site of attack, different products can be formed.

6. **Chiral Center Formation:**
- The product formed from the nucleophilic attack will have a chiral center:
```
CH3-CH(OH)-CH2-CH3
```
- This chiral center can exist in two enantiomeric forms (R and S configurations).

7. **Geometric Isomerism:**
- The presence of the double bond in the product allows for geometric isomerism (cis and trans forms).
- Thus, we can have two geometric isomers from the product.

8. **Total Products:**
- From the chiral center, we get 2 enantiomers.
- From the geometric isomerism, we also get 2 isomers.
- Therefore, the total number of products = 2 (from chiral center) + 2 (from geometric isomerism) = 4 products.

### Conclusion:
- **Statement 1** is true: 3-Chlorobut-1-ene reacts with water to give four products.
- **Statement 2** is also true: The intermediate is a carbocation that shows resonance and racemization.

### Final Answer:
Both statements are true, and Statement 2 is the correct explanation for Statement 1.

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