Match the followng
`{:("Column I","Column II"),((A)CH_3CH_2Clunderset("Cul")overset(Li)tooverset(CH_3CH_2Cl)to?,(p)(CH_3)_2CHCH_2CH(CH_3)_2),((B)(CH_3)_2CHIunderset("Cul")overset(Li)tooverset((CH_3)_2CHCH_2Br)to?,(q)CH_3-CH_2-CH_2-CH_3),(( C)CH_3CH_2C(CH_3)_2Brunderset("Cul")overset(Li)overset(CH_3CH_2Br)to?,(r)(CH_3)_3C CH_2CH_3),((D)(CH_3)_3C Clunderset("Cul")overset(Li)tooverset(CH_3CH_2-Br)to?,(s)CH_3CH_2C(CH_3)_2CH_2CH_3),(,(t)(CH_3)_3C-C(CH_3)_3):}`

Explanation

To solve the matching problem between Column I and Column II, we will analyze each reaction in Column I and determine the corresponding product from Column II.

### Step-by-Step Solution:

1. **Reaction A: CH₃CH₂Cl with Li and CuI**
- The reaction involves CH₃CH₂Cl (ethyl chloride) reacting with lithium and copper iodide.
- This reaction forms an organolithium compound (CH₃CH₂Li) and then reacts with CH₃CH₂Br (ethyl bromide) to form a longer-chain alkane.
- The product formed is CH₃-CH₂-CH₂-CH₃ (butane).
- **Match:** A → Q

2. **Reaction B: (CH₃)₂CHI with Li and CuI**
- Here, (CH₃)₂CHI (isopropyl iodide) reacts with lithium and copper iodide.
- This reaction leads to the formation of (CH₃)₂C=CH₂ (propene) after reacting with CH₃Br.
- The product formed is (CH₃)₂C-CH₂-CH(CH₃)₂ (2-pentene).
- **Match:** B → P

3. **Reaction C: CH₃CH₂C(CH₃)₂Br with Li and CuI**
- In this case, CH₃CH₂C(CH₃)₂Br (tert-butyl bromide) reacts with lithium and copper iodide.
- The reaction results in the formation of CH₃CH₂C(CH₃)₂ (isobutane) after reacting with CH₃CH₂Br.
- The product formed is CH₃CH₂C(CH₃)₂CH₂CH₃ (pentane).
- **Match:** C → S

4. **Reaction D: (CH₃)₃CCl with Li and CuI**
- The reaction of (CH₃)₃CCl (tert-butyl chloride) with lithium and copper iodide leads to the formation of (CH₃)₃C-Li.
- This then reacts with CH₃CH₂Br to yield (CH₃)₃C-CH₂-CH₃ (2-methylbutane).
- The product formed is (CH₃)₃C-CH₂-CH₃ (isobutane).
- **Match:** D → R

### Final Matches:
- A → Q
- B → P
- C → S
- D → R