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Mole fraction of ethyl alcohol in aqueou...

Mole fraction of ethyl alcohol in aqueous ethyl alcohol (`C_2H_5OH`) solution is 0.75. Hence percentage of ethyl alcohol by weight is:

A

81.42%

B

88.46%

C

32.45%

D

74.45%

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The correct Answer is:
To find the percentage of ethyl alcohol (ethanol, C₂H₅OH) by weight in an aqueous solution where the mole fraction of ethyl alcohol is 0.75, we can follow these steps: ### Step 1: Understand the mole fraction The mole fraction (X) of ethyl alcohol is given as 0.75. This means that in a mixture of ethyl alcohol and water, 75% of the moles are ethyl alcohol and 25% are water. ### Step 2: Define the moles of components Let’s assume we have 1 mole of the solution. - Moles of ethyl alcohol (C₂H₅OH) = 0.75 moles - Moles of water (H₂O) = 1 - 0.75 = 0.25 moles ### Step 3: Calculate the mass of ethyl alcohol The molar mass of ethyl alcohol (C₂H₅OH) is 46 g/mol. Therefore, the mass of ethyl alcohol in the solution is: \[ \text{Mass of ethyl alcohol} = \text{Moles} \times \text{Molar mass} = 0.75 \, \text{moles} \times 46 \, \text{g/mol} = 34.5 \, \text{g} \] ### Step 4: Calculate the mass of water The molar mass of water (H₂O) is 18 g/mol. Therefore, the mass of water in the solution is: \[ \text{Mass of water} = \text{Moles} \times \text{Molar mass} = 0.25 \, \text{moles} \times 18 \, \text{g/mol} = 4.5 \, \text{g} \] ### Step 5: Calculate the total mass of the solution The total mass of the solution is the sum of the masses of ethyl alcohol and water: \[ \text{Total mass of solution} = \text{Mass of ethyl alcohol} + \text{Mass of water} = 34.5 \, \text{g} + 4.5 \, \text{g} = 39 \, \text{g} \] ### Step 6: Calculate the percentage by weight of ethyl alcohol The percentage by weight of ethyl alcohol in the solution is given by: \[ \text{Percentage of ethyl alcohol} = \left( \frac{\text{Mass of ethyl alcohol}}{\text{Total mass of solution}} \right) \times 100 \] Substituting the values: \[ \text{Percentage of ethyl alcohol} = \left( \frac{34.5 \, \text{g}}{39 \, \text{g}} \right) \times 100 \approx 88.46\% \] ### Final Answer The percentage of ethyl alcohol by weight in the solution is approximately **88.46%**. ---

To find the percentage of ethyl alcohol (ethanol, C₂H₅OH) by weight in an aqueous solution where the mole fraction of ethyl alcohol is 0.75, we can follow these steps: ### Step 1: Understand the mole fraction The mole fraction (X) of ethyl alcohol is given as 0.75. This means that in a mixture of ethyl alcohol and water, 75% of the moles are ethyl alcohol and 25% are water. ### Step 2: Define the moles of components Let’s assume we have 1 mole of the solution. - Moles of ethyl alcohol (C₂H₅OH) = 0.75 moles ...
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