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If true enter 1, else enter 0.
`sp^2` hybrid orbitals have equal s and p character.

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To determine whether the statement "sp² hybrid orbitals have equal s and p character" is true or false, we need to analyze the hybridization process and the character of the orbitals involved. ### Step-by-Step Solution: 1. **Understanding sp² Hybridization**: - In sp² hybridization, one s orbital and two p orbitals combine to form three equivalent hybrid orbitals. - The notation "sp²" indicates that one s orbital and two p orbitals are involved in the hybridization process. 2. **Calculating the Character of Hybrid Orbitals**: - The total number of orbitals involved in sp² hybridization is 3 (1 s + 2 p). - To find the percentage character of each type of orbital in the hybrid orbitals, we can use the following formulas: - s character = (number of s orbitals / total number of orbitals) × 100 - p character = (number of p orbitals / total number of orbitals) × 100 3. **Calculating s Character**: - For sp²: - s character = (1 s orbital / 3 total orbitals) × 100 = (1/3) × 100 ≈ 33.33% 4. **Calculating p Character**: - For sp²: - p character = (2 p orbitals / 3 total orbitals) × 100 = (2/3) × 100 ≈ 66.67% 5. **Conclusion**: - Since the s character is approximately 33.33% and the p character is approximately 66.67%, they are not equal. - Therefore, the statement "sp² hybrid orbitals have equal s and p character" is **false**. ### Final Answer: Since the statement is false, we enter **0**. ---

To determine whether the statement "sp² hybrid orbitals have equal s and p character" is true or false, we need to analyze the hybridization process and the character of the orbitals involved. ### Step-by-Step Solution: 1. **Understanding sp² Hybridization**: - In sp² hybridization, one s orbital and two p orbitals combine to form three equivalent hybrid orbitals. - The notation "sp²" indicates that one s orbital and two p orbitals are involved in the hybridization process. ...
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According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

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