Compounds P`(C_6H_10)` does not have any geometrical isomer.On ozonolysis, two products `R(C_3H_4O)` and `Q(C_3H_6O)` are formed.R gives negative iodoform test while Q responds positively towards `I_2//NaOH` solution.S, another isomer of P is an unsymetrical alkene and on ozonolysis produces `T(C_6H_(10_7))` which also gives a yellow precipitate with `l_2//NaOH` solution and also positive test with Tollen's reagent Which of the following does not represent any of the molecules amongst P,Q,R,S & T.

Options

A.
B.
C.
D.

Explanation

To solve the problem, we need to analyze the given compounds and their properties step-by-step.

### Step 1: Analyze Compound P (C₆H₁₀)
- Compound P does not have any geometrical isomers, which suggests it has a symmetrical structure.
- A possible structure for P could be 2,3-dimethyl-2-butene, which has no geometrical isomers.

### Step 2: Ozonolysis of Compound P
- Upon ozonolysis, P yields two products: R (C₃H₄O) and Q (C₃H₆O).
- R gives a negative iodoform test, indicating it does not have a methyl ketone group (–C(=O)CH₃).
- Q gives a positive iodoform test, indicating it has a methyl ketone group.

### Step 3: Identify Structures of R and Q
- Since R does not give a positive iodoform test, it could be an aldehyde or an alcohol. A possible structure for R is propanal (CH₃CH₂CHO).
- For Q, since it gives a positive iodoform test, it could be a methyl ketone. A possible structure for Q is 2-butanone (CH₃C(=O)CH₂CH₃).

### Step 4: Analyze Compound S
- S is another isomer of P and is an unsymmetrical alkene.
- Upon ozonolysis, S produces T (C₆H₈O), which gives a yellow precipitate with I₂/NaOH (indicating a positive iodoform test) and a positive test with Tollens' reagent (indicating an aldehyde).

### Step 5: Identify Structure of T
- Since T gives a yellow precipitate with I₂/NaOH, it must contain a methyl ketone group.
- A possible structure for T could be 3-hexanone, which can also yield an aldehyde upon ozonolysis.

### Step 6: Evaluate Given Options
- We need to identify which of the given compounds does not correspond to any of the structures P, Q, R, S, or T.
- If we analyze the molecular formulas and the properties of the compounds, we can conclude that:
- Compound A (C₃H₄O) could be R.
- Compound B (C₆H₈O₂) does not fit any of the identified compounds.
- Compound C (C₆H₁₀O) could be T.
- Compound D (C₃H₆O) could be Q.

### Conclusion
- The compound that does not represent any of the molecules among P, Q, R, S, and T is **Compound B (C₆H₈O₂)**.