Compound X and Y both have the same molecular formula `(C_4H_8O)`.They give following observation in some lab test.
`{:("Test",X,Y),(Br_2-"water","positive","negative"),("Na-matel","positive","negative"),("Lucas reagent","turbidity after some time","negative"),("Iodoform test","negitive","negative"):}`
The compound X and Y are

Options

A.
B.
C.
D.

Answer

To determine the structures of compounds X and Y based on the given observations, we can analyze the results of each test step by step.

### Step 1: Analyze the Bromine Water Test
- **Observation**: X is positive, Y is negative.
- **Interpretation**: A positive result for X indicates that it likely contains a double bond (alkene) or an unsaturated compound that can react with bromine water. The negative result for Y suggests it does not have a double bond, indicating it might be a saturated compound.

### Step 2: Analyze the Sodium Metal Test
- **Observation**: X is positive, Y is negative.
- **Interpretation**: A positive result for X indicates the presence of an alcohol (since alcohols react with sodium metal to produce hydrogen gas). The negative result for Y suggests it does not contain an alcohol group.

### Step 3: Analyze the Lucas Reagent Test
- **Observation**: X shows turbidity after some time, Y is negative.
- **Interpretation**: The turbidity in the case of X indicates that it is likely a secondary or tertiary alcohol, which reacts with Lucas reagent to form an alkyl halide. The negative result for Y suggests it is not an alcohol, which aligns with the previous observations.

### Step 4: Analyze the Iodoform Test
- **Observation**: Both X and Y are negative.
- **Interpretation**: The negative result for the Iodoform test indicates that neither compound has a methyl ketone or a structure that can be oxidized to form one. This suggests that both compounds do not have the required structure for this test.

### Conclusion
Based on the above analysis:
- **Compound X**: It is likely a secondary alcohol (due to positive tests for bromine water and sodium metal, and turbidity with Lucas reagent) that does not have a methyl group adjacent to the carbon bearing the hydroxyl group (thus negative for Iodoform test). A possible structure could be 3-pentanol.
- **Compound Y**: It is likely an ether or a saturated compound (due to negative results for all tests). A possible structure could be 1-butanol or an ether like diethyl ether.

### Final Structures
- **Compound X**: 3-Pentanol (or a similar secondary alcohol)
- **Compound Y**: 1-Butanol (or a similar saturated compound)