An aromatic compound T `(C_10H_10O_2)` gives 2 moles of `CHI_2` and compound U `(C_8H_4O_4Na)` on treatment with `I_2`.and NaOH . After acidification U gives two mononitro products on nitration.
Compound U is

Options

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D.

Explanation

To solve the problem, we need to determine the structure of compound U (C8H4O4Na) based on the information provided. Here’s a step-by-step breakdown of the solution:

### Step 1: Analyze the given information
- We have an aromatic compound T with the formula C10H10O2.
- Upon treatment with I2 and NaOH, compound T yields 2 moles of CHI2 and compound U (C8H4O4Na).
- After acidification, compound U can undergo nitration to give two mononitro products.

### Step 2: Determine the structure of compound T
- The molecular formula C10H10O2 suggests that compound T is likely a substituted aromatic compound.
- The presence of 2 moles of CHI2 indicates that there are two methyl groups adjacent to a carbonyl group (as the reaction involves the formation of iodoform).

### Step 3: Identify the structure of compound U
- After the reaction, compound U has the formula C8H4O4Na. This suggests that U is a sodium salt of a dicarboxylic acid.
- The presence of two carboxylate groups (from the formula) indicates that U could be a derivative of phthalic acid.

### Step 4: Consider the nitration of compound U
- The fact that U gives two mononitro products upon nitration suggests that U has two positions available for substitution on the aromatic ring.
- This is consistent with the structure of sodium phthalate (the sodium salt of phthalic acid), which has two available positions for nitration.

### Step 5: Conclude the structure of compound U
- Based on the above analysis, compound U is likely sodium phthalate (C8H4O4Na).

### Final Answer
Compound U is sodium phthalate (C8H4O4Na).

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