`X(C_8H_14)` by ozonolysis forms `Y[C_8H_14O_2]`.Y on reaction with NaOI followed by acidification gives `CHI_3` and compound Z on strong heating froms W.
`{:("Column-I","Column-II"),((A)"Compound X","(p)Bayer's Test"),((B)"Compound Y",(q)NaHCO_3),(( C)"Compound Z","(r)2, 4-DNP"),((D)"Compound W","(s)Iodoform Test"),(,"(t)Na Metal"):}`

Explanation

To solve the problem, we need to identify the compounds X, Y, Z, and W based on the information given about their structures and reactions. Let's break it down step by step.

### Step 1: Identify Compound X (C8H14)
- We know that compound X is an alkene with the formula C8H14.
- Ozonolysis of alkenes typically breaks the double bond and adds oxygen to form carbonyl compounds.
- Given that ozonolysis of X forms Y (C8H14O2), we can deduce that X is likely a cyclic alkene due to the presence of a symmetrical structure.
- The structure of X can be drawn as a symmetrical cyclic alkene, such as 1,2-dimethylcyclohexene.

**Hint:** Look for a symmetrical structure that fits the formula C8H14.

### Step 2: Identify Compound Y (C8H14O2)
- Ozonolysis of X results in Y, which has the formula C8H14O2.
- The ozonolysis reaction typically converts double bonds into carbonyl groups (C=O).
- Thus, Y is likely a dicarbonyl compound formed from the cleavage of the double bond in X.

**Hint:** Consider the products of ozonolysis and how they relate to the structure of X.

### Step 3: Identify Compound Z
- Y reacts with NaOI followed by acidification to yield CHI3 and compound Z.
- The formation of CHI3 indicates that Z must contain a methyl ketone functional group (as iodoform test is positive for methyl ketones).
- Since Y has two carbonyl groups, Z is likely a carboxylic acid formed from the oxidation of Y.

**Hint:** Look for a compound that can yield CHI3 upon reaction with NaOI and acidification.

### Step 4: Identify Compound W
- Z, upon strong heating, forms W.
- Since Z is a carboxylic acid, heating it can lead to decarboxylation or rearrangement to form a simpler compound.
- W is likely a hydrocarbon or a simpler ketone.

**Hint:** Consider the products of thermal decomposition of carboxylic acids.

### Step 5: Match Compounds with Tests
Now we need to match the compounds with the tests provided in Column-II.

- **Compound X (C8H14)**: This will give a positive result for Bayer's Test (p) because it contains a carbon-carbon double bond.
- **Compound Y (C8H14O2)**: This will give a positive result for 2,4-DNP test (r) as it contains carbonyl groups.
- **Compound Z**: This will give a positive result for NaHCO3 test (q) because it is a carboxylic acid.
- **Compound W**: This will give a positive result for Iodoform Test (s) if it contains a methyl ketone.

### Final Answers:
- **A**: Compound X → (p) Bayer's Test
- **B**: Compound Y → (r) 2, 4-DNP Test
- **C**: Compound Z → (q) NaHCO3 Test
- **D**: Compound W → (s) Iodoform Test

### Summary of Identifications:
- **X**: 1,2-dimethylcyclohexene
- **Y**: Dicarbonyl compound
- **Z**: Carboxylic acid
- **W**: A simpler ketone or hydrocarbon