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The possible number of stereoisomers of ...

The possible number of stereoisomers of the product of following reaction would be :
`Ph-CH=CH-undersetunderset(CH_3)(|)CH-CHOoverset(NH_2OH)to`

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Product=`Ph-CH=CH-undersetunderset(CH_3)(|)CH-CH=NOH`
Total number of stereoisomers =`2^(n)=2^(3)=8`
(n = number of stereo centres (G.I.+O.I.)=2+1=3)
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