When Benzene-1,3-dicarbaldehyde react with 50% NaOH.The products formed is/are :

Options

A.
B.
C.
D.

Explanation

To solve the problem of what products are formed when benzene-1,3-dicarbaldehyde reacts with 50% NaOH, we can follow these steps:

### Step 1: Identify the structure of benzene-1,3-dicarbaldehyde
Benzene-1,3-dicarbaldehyde has two aldehyde groups (-CHO) attached to the benzene ring at the 1 and 3 positions. The structure can be represented as follows:

```
O
||
C6H4 - C - C - H
||
O
```

### Step 2: Understand the reaction type
The reaction of benzene-1,3-dicarbaldehyde with a strong base like NaOH is known as the Cannizzaro reaction. This reaction occurs with non-enolizable aldehydes, where one aldehyde group is oxidized to a carboxylic acid while the other is reduced to an alcohol.

### Step 3: Determine the products
In the Cannizzaro reaction, since there are two aldehyde groups, we can expect multiple products due to the possibility of both inter- and intramolecular reactions.

1. **Both aldehyde groups oxidized**: This will yield sodium salt of a dicarboxylic acid.
- Product: COO⁻ Na⁺ (sodium salt of a carboxylic acid)

2. **One aldehyde group oxidized, one reduced**: This will yield one alcohol and one sodium salt of a carboxylic acid.
- Product: One position will have CH2OH (benzyl alcohol) and the other will have COO⁻ Na⁺.

3. **Both aldehyde groups reduced**: This will yield a diol.
- Product: Both positions will have CH2OH (benzyl alcohol).

### Step 4: List all possible products
From the above reactions, we can summarize the products formed:
1. Sodium salt of dicarboxylic acid (COO⁻ Na⁺)
2. One benzyl alcohol (CH2OH) and one sodium salt of a carboxylic acid (COO⁻ Na⁺)
3. Two benzyl alcohols (CH2OH)

### Final Answer:
The products formed when benzene-1,3-dicarbaldehyde reacts with 50% NaOH are:
1. Sodium salt of dicarboxylic acid
2. Benzyl alcohol and sodium salt of a carboxylic acid
3. Two benzyl alcohols