State true or false
SnCl4 is more covalent than SnCl2 ​ .

Explanation

To determine whether the statement "SnCl4 is more covalent than SnCl2" is true or false, we can analyze the oxidation states and polarizing power of the central atom, tin (Sn), in both compounds.

### Step-by-Step Solution:

1. **Identify the Oxidation States**:
- In SnCl4, the oxidation state of Sn is +4.
- In SnCl2, the oxidation state of Sn is +2.

2. **Understand Polarizing Power**:
- The polarizing power of a cation increases with an increase in its charge and a decrease in its size.
- Since Sn in SnCl4 has a higher oxidation state (+4) compared to Sn in SnCl2 (+2), it has a greater polarizing power.

3. **Relate Polarizing Power to Covalent Character**:
- Higher polarizing power leads to a greater ability to distort the electron cloud of the anion (Cl in this case).
- This distortion increases the covalent character of the bond formed between the central atom (Sn) and the anions (Cl).

4. **Conclusion**:
- Since SnCl4 has a higher oxidation state (+4) than SnCl2 (+2), it exhibits greater polarizing power, which in turn increases its covalent character.
- Therefore, we can conclude that SnCl4 is indeed more covalent than SnCl2.

5. **Final Answer**:
- The statement "SnCl4 is more covalent than SnCl2" is **True**.