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{:("Column-I","Column-II"),((A)C2H5-over...

`{:("Column-I","Column-II"),((A)C_2H_5-oversetoverset(O)(||)C-OH-overset(C_2H_5O^(Theta))to,(p)"Hydrolysis"),((B)C_2H_5-oversetoverset(O)(||)C-OH-overset(o+)overset(C_2H_5OH//H)to,(q)"Esterification"),((C )C_2H_5-oversetoverset(O)(||)C-OC_2H_5overset(H_3O^(o+))to,(r)"Saponification"),((D)C_2H_5-oversetoverset(O)(||)C-OC_2H_5overset(Theta)overset(OH)to,(s)"Acid base solution"),(,""):}`

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The correct Answer is:
To solve the question, we need to match the reactions from Column I with their corresponding types from Column II. Let's analyze each reaction step by step. ### Step 1: Analyze Reaction A - **Reaction A**: C2H5C(=O)OH + C2H5O^(-) → ? - Here, we have an acid (C2H5C(=O)OH) reacting with an alkoxide ion (C2H5O^(-)). - The product formed will be an anion (C2H5COO^(-)) and an alcohol (C2H5OH). - This reaction can be classified as an **acid-base reaction** because it involves the transfer of a proton (H^+) from the acid to the alkoxide ion. ### Conclusion for Reaction A: - **Match**: A → S (Acid-base solution) ### Step 2: Analyze Reaction B - **Reaction B**: C2H5C(=O)OH + C2H5OH (in presence of H^+) → ? - This is a classic esterification reaction where a carboxylic acid (C2H5C(=O)OH) reacts with an alcohol (C2H5OH) in the presence of an acid catalyst (H^+). - The product formed will be an ester (C2H5C(=O)O-C2H5) and water. ### Conclusion for Reaction B: - **Match**: B → Q (Esterification) ### Step 3: Analyze Reaction C - **Reaction C**: C2H5C(=O)O-C2H5 + H3O^+ → ? - This reaction involves the hydrolysis of an ester (C2H5C(=O)O-C2H5) in the presence of an acid (H3O^+). - The products will be the corresponding carboxylic acid (C2H5C(=O)OH) and an alcohol (C2H5OH). - This is a **hydrolysis reaction**. ### Conclusion for Reaction C: - **Match**: C → P (Hydrolysis) ### Step 4: Analyze Reaction D - **Reaction D**: C2H5C(=O)O-C2H5 + OH^(-) → ? - In this case, the ester (C2H5C(=O)O-C2H5) is being hydrolyzed in the presence of a base (OH^(-)). - This reaction is specifically known as **saponification**, where an ester reacts with a base to form a carboxylate ion and an alcohol. ### Conclusion for Reaction D: - **Match**: D → R (Saponification) ### Final Matches: - A → S (Acid-base solution) - B → Q (Esterification) - C → P (Hydrolysis) - D → R (Saponification) ### Summary of Matches: - A - S - B - Q - C - P - D - R

To solve the question, we need to match the reactions from Column I with their corresponding types from Column II. Let's analyze each reaction step by step. ### Step 1: Analyze Reaction A - **Reaction A**: C2H5C(=O)OH + C2H5O^(-) → ? - Here, we have an acid (C2H5C(=O)OH) reacting with an alkoxide ion (C2H5O^(-)). - The product formed will be an anion (C2H5COO^(-)) and an alcohol (C2H5OH). - This reaction can be classified as an **acid-base reaction** because it involves the transfer of a proton (H^+) from the acid to the alkoxide ion. ...
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