Statement-1:Pentacetate of glucose does not form oxime on treatment with `H_2N-OH`
Statement-2:Glucose on reaction with acetic anhydride forms pentacetate under suitable conditions.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the given question, we need to analyze both statements regarding glucose and its derivatives.

### Step-by-Step Solution:

1. **Understanding Statement 1**:
- Statement 1 claims that "Pentacetate of glucose does not form oxime on treatment with `H2N-OH`."
- To evaluate this, we need to know that glucose can form a pentacetate when treated with acetic anhydride. The pentacetate has all five hydroxyl groups of glucose replaced by acetate groups.
- The oxime formation typically occurs when an aldehyde or ketone reacts with hydroxylamine (`H2N-OH`). However, in the case of glucose pentacetate, the hydroxyl group at C1 is converted to an acetate group, which means that the aldehyde form of glucose is not available for oxime formation.
- Therefore, Statement 1 is **True**.

2. **Understanding Statement 2**:
- Statement 2 states that "Glucose on reaction with acetic anhydride forms pentacetate under suitable conditions."
- This reaction is indeed valid. When glucose reacts with acetic anhydride in the presence of a catalyst (like anhydrous zinc chloride), all five hydroxyl groups of glucose can be acetylated, leading to the formation of glucose pentacetate.
- Thus, Statement 2 is also **True**.

3. **Evaluating the Relationship Between the Statements**:
- Now, we need to determine if Statement 2 provides a correct explanation for Statement 1.
- While both statements are true, Statement 2 explains how glucose can be converted into pentacetate, but it does not explain why pentacetate does not form oxime. The lack of an aldehyde group in the pentacetate is the reason for the non-formation of oxime, which is not directly addressed in Statement 2.
- Therefore, Statement 2 is not the correct explanation for Statement 1.

4. **Conclusion**:
- Both statements are true, but Statement 2 does not serve as a correct explanation for Statement 1. Hence, the correct answer is that both statements are true, but Statement 2 is not the correct explanation for Statement 1.

### Final Answer:
- **Option 2**: Statement 1 is true, Statement 2 is true, and Statement 2 is not the correct explanation for Statement 1.