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Decreasing order of boiling point of I t...

Decreasing order of boiling point of I to IV follow
`{:("Methylformate","Ethylformate","Iso-propylformate","n-Propylformate"),(I,II,III,IV):}`

A

`IgtIIgtIIIgtIV`

B

`IIIgtIVgtIIgtI`

C

`IVgtIIIgtIIgtI`

D

`IgtIIgtIVgtIII`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the decreasing order of boiling points for the compounds: Methylformate (I), Ethylformate (II), Isopropylformate (III), and n-Propylformate (IV), we can follow these steps: ### Step 1: Understand the Structures - **Methylformate (I)**: Contains one methyl group (CH3). - **Ethylformate (II)**: Contains one ethyl group (C2H5). - **Isopropylformate (III)**: Contains a branched isopropyl group (C3H7). - **n-Propylformate (IV)**: Contains a straight-chain propyl group (C3H7). ### Step 2: Analyze Molecular Weights - Methylformate has the lowest molecular weight due to having the smallest alkyl group. - Ethylformate has a higher molecular weight than methylformate. - Isopropylformate and n-Propylformate have similar molecular weights, but the structure differs (branched vs. straight chain). ### Step 3: Determine the Effect of Molecular Weight on Boiling Point - Generally, the boiling point increases with increasing molecular weight due to stronger van der Waals forces. - Methylformate (I) will have the lowest boiling point due to the lowest molecular weight. - Ethylformate (II) will have a higher boiling point than methylformate due to its higher molecular weight. ### Step 4: Compare Isopropylformate and n-Propylformate - Between Isopropylformate (III) and n-Propylformate (IV), the straight-chain n-Propylformate (IV) will have a higher boiling point than the branched Isopropylformate (III) because straight-chain molecules have stronger intermolecular forces compared to branched ones. ### Step 5: Arrange in Decreasing Order Based on the analysis: 1. **n-Propylformate (IV)** - Highest boiling point 2. **Isopropylformate (III)** 3. **Ethylformate (II)** 4. **Methylformate (I)** - Lowest boiling point ### Final Order The decreasing order of boiling points is: **IV > III > II > I**

To determine the decreasing order of boiling points for the compounds: Methylformate (I), Ethylformate (II), Isopropylformate (III), and n-Propylformate (IV), we can follow these steps: ### Step 1: Understand the Structures - **Methylformate (I)**: Contains one methyl group (CH3). - **Ethylformate (II)**: Contains one ethyl group (C2H5). - **Isopropylformate (III)**: Contains a branched isopropyl group (C3H7). - **n-Propylformate (IV)**: Contains a straight-chain propyl group (C3H7). ...
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