Different reagents used for the identification of different functional groups.
Eg. (i)Tollens reagent used for the identification of -CHO, etc.
(ii)CAN used for alcohol.
`{:("Column-I","Column-II","Column-III"),((I)"Benzaldehyde",(i)l_2+NaOH(aq.),(P)"Yellow crystals is formed"),((II)"Butan-1-ol",(ii)AgNO_3(aq.)+NH_4OH,(Q)"White ppt is formed"),((III)"Formic ester",(iii)anhy.ZnCl_2+conc.HCl,(R)"Silver mirror is formed"),((IV)"Acetophenone",(iv)(NH_4)_2[Ce(NO_3)_6](CAN),(S)"Wine red colouration"):}`
For the formation of two different organic compounds the only correct combination is :

Options

A. (I),(ii),(R)
B. (IV),(i)(P)
C. (II)(iii)(Q)
D. (IV),(ii)(R)

Explanation

To solve the question regarding the identification of different functional groups using specific reagents, we will analyze the combinations given in the columns step by step.

### Step 1: Understanding the Reagents and Their Functions
We have the following reagents:
1. **I2 + NaOH (Iodoform Reaction)** - This reagent is used to identify compounds with a methyl ketone group (R-CO-CH3).
2. **AgNO3 + NH4OH (Tollens' Reagent)** - This reagent is used to identify aldehydes, which can reduce silver ions to metallic silver.
3. **Anhydrous ZnCl2 + conc. HCl** - This is used in the Lucas test to identify alcohols.
4. **(NH4)2[Ce(NO3)6] (Cerium Ammonium Nitrate, CAN)** - This reagent is used for the identification of alcohols.

### Step 2: Analyzing Each Compound in Column I
1. **Benzaldehyde** - This is an aldehyde and will react with Tollens' reagent to give a silver mirror. It does not give iodoform reaction since it does not have a methyl ketone structure.

2. **Butan-1-ol** - This is a primary alcohol. It will react with CAN to give a wine red coloration, but it does not give iodoform reaction.

3. **Formic ester** - This is an ester and does not give iodoform reaction. However, it can be hydrolyzed to form formic acid and alcohol.

4. **Acetophenone** - This is a ketone with a methyl group adjacent to the carbonyl group. It will react with I2 + NaOH to give iodoform (CHI3) and an acidic salt.

### Step 3: Identifying the Correct Combinations
Now, we will match the compounds from Column I with the reagents from Column II and their respective observations in Column III.

- **(I) Benzaldehyde**: Reacts with (ii) AgNO3 + NH4OH → (R) Silver mirror is formed.
- **(II) Butan-1-ol**: Reacts with (iv) (NH4)2[Ce(NO3)6] (CAN) → (S) Wine red coloration.
- **(III) Formic ester**: Does not have a clear match among the reagents provided.
- **(IV) Acetophenone**: Reacts with (i) I2 + NaOH → (P) Yellow crystals are formed (CHI3).

### Step 4: Finding the Correct Combination
From our analysis, we see that:
- **Acetophenone** (IV) with **I2 + NaOH** (i) gives **Yellow crystals (P)**.
- **Benzaldehyde** (I) with **AgNO3 + NH4OH** (ii) gives **Silver mirror (R)**.

The only combination that results in two different organic compounds is:
- **Acetophenone (IV)** with **I2 + NaOH (i)** resulting in **Yellow crystals (P)**.

### Conclusion
The only correct combination that leads to the formation of two different organic compounds is:
- **(IV) Acetophenone**, **(i) I2 + NaOH**, and **(P) Yellow crystals are formed**.

Thus, the answer is **Option B: 4, 1, P**.

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