The velocity corresponding to a gas "X" (MW=100) corresponding to the maxima of the curve given below at a given temperature is 200 m/s.Then kinetic energy of 300 gram of has "X" will be

Options

A. 9000 kJ
B. 9 kJ
C. 90 kJ
D. 810 kJ

Answer

B

Explanation

The velocity corresponding to the maxima is the most probable velocity which is given by the expression
`C_(np)=sqrt((2RT)/M)`
`RT=(C_(mp)^2M)/2=((200)^2xx100xx10^(-3))/2=40000xx50xx10^(-3) J mol^(-1) = 40xx50 J mol^(-1)`
No of moles =`300/100=3`
`E=3/2nRT=3/2xx3xx40xx50=9xx10^(3) J =9 kJ`