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30 ml of 0.06 M solution of the protonat...

30 ml of 0.06 M solution of the protonated form of an anion of acid methonime `(H_(2)A^(+))` is treated with 0.09 M NaOH. Calculate pH after addition of 20 ml of base. [`pKa_(1)= 2.28` and `pKa_(2)=9.2`]

A

5.5

B

5.74

C

9.5

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
`pH=(pK_(a_1)+pK_(a_2))/2 =(2.28+9.2)/2=5.74`
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