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Calculate the weight of lime (CaO) obtai...

Calculate the weight of lime (CaO) obtained by heating 190kg of 95% pure lime stone (`CaCO_3`).
`CaCO_3​→CaO+CO_2` ​

A

101Kg

B

202Kg

C

303Kg

D

404Kg

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the weight of lime (CaO) obtained by heating 190 kg of 95% pure limestone (CaCO₃), we can follow these steps: ### Step 1: Calculate the amount of pure CaCO₃ First, we need to determine the amount of pure CaCO₃ in the limestone. Since the limestone is 95% pure, we calculate: \[ \text{Pure CaCO}_3 = 95\% \text{ of } 190 \text{ kg} \] \[ \text{Pure CaCO}_3 = \frac{95}{100} \times 190 = 180.5 \text{ kg} \] ### Step 2: Convert kg to grams Next, we convert the amount of pure CaCO₃ from kilograms to grams, since the molar masses are typically expressed in grams. \[ \text{Pure CaCO}_3 = 180.5 \text{ kg} \times 1000 \text{ g/kg} = 180500 \text{ g} \] ### Step 3: Write the balanced chemical equation The decomposition of calcium carbonate (CaCO₃) can be represented by the following equation: \[ \text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2 \] From this equation, we see that 1 mole of CaCO₃ produces 1 mole of CaO. ### Step 4: Determine the molar masses Next, we need the molar masses of CaCO₃ and CaO: - Molar mass of CaCO₃ = 100 g/mol - Molar mass of CaO = 56 g/mol ### Step 5: Calculate the amount of CaO produced Using the stoichiometry of the reaction, we can find out how much CaO is produced from the amount of CaCO₃ we have. The ratio of CaO produced to CaCO₃ is: \[ \text{Mass of CaO} = \left(\frac{\text{Molar mass of CaO}}{\text{Molar mass of CaCO}_3}\right) \times \text{Mass of CaCO}_3 \] Substituting in the values we have: \[ \text{Mass of CaO} = \left(\frac{56 \text{ g}}{100 \text{ g}}\right) \times 180500 \text{ g} \] Calculating this gives: \[ \text{Mass of CaO} = 0.56 \times 180500 = 101080 \text{ g} \] ### Step 6: Convert grams to kilograms Finally, we convert the mass of CaO from grams back to kilograms: \[ \text{Mass of CaO} = \frac{101080 \text{ g}}{1000 \text{ g/kg}} = 101.08 \text{ kg} \] ### Final Answer The weight of lime (CaO) obtained by heating 190 kg of 95% pure limestone is approximately **101.08 kg**. ---

To calculate the weight of lime (CaO) obtained by heating 190 kg of 95% pure limestone (CaCO₃), we can follow these steps: ### Step 1: Calculate the amount of pure CaCO₃ First, we need to determine the amount of pure CaCO₃ in the limestone. Since the limestone is 95% pure, we calculate: \[ \text{Pure CaCO}_3 = 95\% \text{ of } 190 \text{ kg} \] ...
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