When boron is fused with potassium hydroxide which pair of species are formed ?

Options

A. `K_2O+B_2O_3`
B. `KO_2B_2H_6`
C. `K_3BO_3+H_2`
D. `K_3BO_3+H_2O`

Explanation

To solve the question "When boron is fused with potassium hydroxide, which pair of species are formed?", we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are boron (B) and potassium hydroxide (KOH).

### Step 2: Write the Reaction
When boron reacts with potassium hydroxide, the reaction can be represented as:
\[ \text{B} + \text{KOH} \rightarrow \text{K}_3\text{BO}_3 + \text{H}_2 \]

### Step 3: Balance the Reaction
To balance the reaction, we need to ensure that the number of atoms for each element is the same on both sides of the equation. The balanced equation is:
\[ 2 \text{B} + 6 \text{KOH} \rightarrow 2 \text{K}_3\text{BO}_3 + 3 \text{H}_2 \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products formed are potassium borate (K3BO3) and hydrogen gas (H2).

### Conclusion
Thus, the pair of species formed when boron is fused with potassium hydroxide is:
- Potassium borate (K3BO3)
- Hydrogen gas (H2)

### Final Answer
The correct answer is K3BO3 and H2.

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