`B_2H_6+NH_3to`Addition compound (X) `overset(450 K)to` Y+Z(g)
In the above sequence Y and Z are respectively :

Options

A. Borazine and hydrogen
B. Boron and hydrogen
C. Boron nitride and hydrogen
D. Borazine and hydrogen

Explanation

To solve the problem, we need to analyze the reaction between diborane (B₂H₆) and ammonia (NH₃) and identify the products formed after heating.

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactants in the reaction are diborane (B₂H₆) and ammonia (NH₃).

2. **Formation of the Addition Compound (X):**
- When diborane reacts with ammonia, they form an addition compound. The reaction can be represented as:
\[ B_2H_6 + 2NH_3 \rightarrow B_2H_6 \cdot 2NH_3 \]
- This compound is called an adduct and is denoted as (X).

3. **Heating the Addition Compound:**
- When the addition compound (X) is heated at 450 K, it undergoes decomposition. The reaction can be represented as:
\[ 2B_2H_6 \cdot 2NH_3 \xrightarrow{450 K} B_3N_3H_6 + 3H_2 \]
- Here, B₃N₃H₆ is formed along with hydrogen gas (H₂).

4. **Identify the Products (Y and Z):**
- From the decomposition reaction:
- Y is B₃N₃H₆ (borazine).
- Z is H₂ (hydrogen gas).

5. **Final Answer:**
- Therefore, the products Y and Z are:
- Y = B₃N₃H₆ (borazine)
- Z = H₂ (hydrogen gas)

### Conclusion:
The correct answer is:
- Y = Borazine (B₃N₃H₆)
- Z = Hydrogen gas (H₂)