In which of the following arrangement, the order is/are according to the property indicated against it ?

Answer

A,B,C,D

Explanation

(A)`SbH_3` has highest boiling point on account of highest magnitude of vander Waals force of attraction due to highest molecular mass. Next is of `NH_3` due to strong H-bonding.
(B)Number of unpaired electron are 5,4,3 & 2 respectively.
Paramagnetic character `prop` Number of unpaired electrons.
( C)Degree of hydration `prop 1/("size of cation ")` Bigger hydrated ion moves slowly.
(D)Bond order is directly proportional to the bond energy.
Bond order of `N_2 =3, N_2^(+)=2.5, N_2^(2-)=2`
But `N_2^-` has more electrons in antibonding MO's and thus `N_2^+` is more stable than `N_2^-`.