Two friends Rohit and John, students of chemistry once discussing on periodic table, reach to a conclusion that because of Aufbau rule and other principles their thoughts are restricted for further discussion on electronic arrangements of atoms.They decided not be obey Aufbau rule and capacity of each orbital is increased to three electrons i.e. instead of two each orbital can take maximum of three electrons.Now on th basis of new arrangement of rohit and john answer the following questions assuming the total no of elements is 112.
What is the block of the elements with atomic number 9,28,44 ?

Options

A. s,p,d
B. p,s,d
C. p,d,s
D. d,p,s

Explanation

To determine the blocks of the elements with atomic numbers 9, 28, and 44 based on the new electronic arrangement proposed by Rohit and John, we will follow these steps:

### Step 1: Identify the Atomic Number and Standard Electronic Configuration
- **Atomic Number 9**: The standard electronic configuration is \(1s^2 2s^2 2p^5\).
- **Atomic Number 28**: The standard electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2\).
- **Atomic Number 44**: The standard electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 5s^2 4d^{10}\).

### Step 2: Modify the Electronic Configuration Based on New Rules
According to Rohit and John's new arrangement, each orbital can hold a maximum of 3 electrons instead of 2.

1. **For Atomic Number 9**:
- New configuration:
- \(1s^3\) (3 electrons in the 1s orbital)
- \(2s^3\) (3 electrons in the 2s orbital)
- \(2p^3\) (3 electrons in the 2p orbital)
- Last electron enters the **p orbital**.
- **Block**: P block.

2. **For Atomic Number 28**:
- New configuration:
- \(1s^3\) (3 electrons in the 1s orbital)
- \(2s^3\) (3 electrons in the 2s orbital)
- \(2p^3\) (3 electrons in the 2p orbital)
- \(3s^3\) (3 electrons in the 3s orbital)
- \(3p^3\) (3 electrons in the 3p orbital)
- \(3d^{15}\) (15 electrons in the 3d orbitals)
- Last electron enters the **d orbital**.
- **Block**: D block.

3. **For Atomic Number 44**:
- New configuration:
- \(1s^3\) (3 electrons in the 1s orbital)
- \(2s^3\) (3 electrons in the 2s orbital)
- \(2p^3\) (3 electrons in the 2p orbital)
- \(3s^3\) (3 electrons in the 3s orbital)
- \(3p^3\) (3 electrons in the 3p orbital)
- \(3d^{15}\) (15 electrons in the 3d orbitals)
- \(4s^3\) (3 electrons in the 4s orbital)
- Last electron enters the **s orbital**.
- **Block**: S block.

### Step 3: Conclusion
Based on the new electronic configurations:
- Atomic Number 9: **P block**
- Atomic Number 28: **D block**
- Atomic Number 44: **S block**

### Final Answer
The blocks of the elements with atomic numbers 9, 28, and 44 are:
- 9: P block
- 28: D block
- 44: S block