In `SIO_2`, each silicon atom is covalently bonded in a tetrahedral manner to four oxygen and each oxygen atom in turn is covalently bonded to another two silicon atoms giving a three dimensional network solid.Find the total number of atoms comprising each ring forming the three dimensional network solid .

Explanation

To solve the problem regarding the three-dimensional network solid structure of SiO₂, we need to analyze the bonding arrangement of silicon and oxygen atoms in the structure.

### Step-by-Step Solution:

1. **Understanding the Structure of SiO₂**:
- Each silicon (Si) atom is tetrahedrally coordinated to four oxygen (O) atoms.
- Each oxygen atom is bonded to two silicon atoms.

2. **Visualizing the Tetrahedral Arrangement**:
- In a tetrahedral arrangement, if we consider one silicon atom at the center, it will be surrounded by four oxygen atoms at the vertices of the tetrahedron.

3. **Formation of Rings**:
- The tetrahedral arrangement of SiO₂ leads to the formation of a three-dimensional network.
- In this network, the arrangement of silicon and oxygen atoms can create cyclic structures or rings.

4. **Identifying the Ring Structure**:
- In the case of SiO₂, the tetrahedral arrangement can form an 8-membered cyclic ring.
- This ring consists of alternating silicon and oxygen atoms.

5. **Counting the Atoms in the Ring**:
- In an 8-membered ring, there are 4 silicon atoms and 4 oxygen atoms.
- Therefore, the total number of atoms in the ring is:
\[ \text{Total atoms} = \text{Number of Si atoms} + \text{Number of O atoms} = 4 + 4 = 8 \]

### Final Answer:
The total number of atoms comprising each ring forming the three-dimensional network solid of SiO₂ is **8**.