An organic compound `X(C_5H_10)` on ozonolysis gives Y & Z. The product mixture Y and Z on reaction with `NH_2-OH` gives four oximes.The structure of X is

Options

A. `CH_3-oversetoverset(CH_2)(||)C-CH_2CH_3`
B. `CH_3-CH=CH-CH_2-CH_3`
C.
D. `H_3C-oversetoverset(CH_3)(|)CH-CH=CH_2`

Explanation

To determine the structure of the organic compound \( X(C_5H_{10}) \) that yields four oximes upon ozonolysis and subsequent reaction with hydroxylamine (\( NH_2OH \)), we can follow these steps:

### Step 1: Understand Ozonolysis
Ozonolysis is a reaction where alkenes are cleaved by ozone to form carbonyl compounds (aldehydes or ketones). The general reaction can be represented as:
\[ R_1C=CR_2 + O_3 \rightarrow R_1C(=O)R_3 + R_2C(=O)R_4 \]

### Step 2: Analyze the Molecular Formula
The molecular formula \( C_5H_{10} \) indicates that the compound is likely an alkene (since it has the general formula \( C_nH_{2n} \)). This suggests that \( X \) could be a pentene.

### Step 3: Consider Possible Structures for \( X \)
Given that ozonolysis of \( X \) results in two products \( Y \) and \( Z \), we can hypothesize several structures of \( X \). The structure must be such that it can yield two different carbonyl compounds upon ozonolysis.

### Step 4: Ozonolysis of Candidate Structures
Let’s consider a potential structure for \( X \):
- **Structure 1**: \( CH_3-CH=CH-CH_2-CH_3 \) (1-pentene)

Ozonolysis of this structure would yield:
- \( CH_3-CH=O \) (an aldehyde)
- \( CH_2=O \) (another aldehyde)

### Step 5: Reaction with Hydroxylamine
The products \( Y \) and \( Z \) from ozonolysis will react with hydroxylamine to form oximes. Each carbonyl compound can form an oxime:
- For \( CH_3CHO \) (acetaldehyde), the oxime formed is \( CH_3C(=NOH)H \).
- For \( CH_2O \) (formaldehyde), the oxime formed is \( H_2C=NOH \).

### Step 6: Count the Oximes
From the ozonolysis products, we can see that:
- Each aldehyde can form an oxime, and if there are two different aldehydes, they can yield different oximes.
- Since we need four oximes, we should consider branching or more complex structures.

### Step 7: Final Structure
After testing several structures, we find that the structure \( CH_3-CH=CH-CH_2-CH_3 \) (2-pentene) gives:
- Ozonolysis products: \( CH_3C(=O)CH_2CH_3 \) and \( CH_2=O \)
- This leads to four distinct oximes upon reaction with \( NH_2OH \):
1. From \( CH_3C(=O)CH_2CH_3 \)
2. From \( CH_2=O \)
3. Different stereoisomers from the same aldehyde.

### Conclusion
The structure of \( X \) is:
\[ \text{2-Pentene} \, (CH_3-CH=CH-CH_2-CH_3) \]