Feo `Cr_(2)O_(3)``underset(O_(2)) overset(Na_(2)CO_(3))toAoverset(H_(2)SO_(4))toBoverset(KCl)toC`
The hybridisation of compound C and colour of its crystal is

Options

A. In all three compounds , the chromium is in +6 oxidation state
B. [Z] is a deep blue -violet coloured compound which decomposes rapidly in aqueous solution into `Cr^(3+)` and dioxygen
C. Saturated solution of [Y] gives bright organge compound , chromic anhydride, with concentrated `H_2SO_4`
D. All of these

Answer

D

Explanation

`4FeCr_2O_4 8Na_2CO_3+7O_2overset("Fusion")tooverset(+VI)(Na_2CrO_4)underset(H_2O)overset(H^+)tooverset(+VI)(Na_2Cr_2O_7)overset(H^+ // H_2O_2)tooverset(+VI)(CrO(O_2)_2)`("deep blue violet")overset(H_2O)toO_2+H_2O+Cr^(3+)`
`Na_2Cr_2O_7+H_2SO_4to2CrO_3("chromic anhydride")+Na_2SO_4+H_2O`