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[Fe(CN)5NO]^(2-)+S^(2-)toProduct[X] An...

`[Fe(CN)_5NO]^(2-)+S^(2-)to`Product[X]
Answer the following questions for the product [X].
(i)Number of negative monodenate ligand(s).
(ii)Effective atomic number of iron in the complex.
(iii)Number of unpaired electrons

Text Solution

Verified by Experts

The correct Answer is:
6,3,6,1

(i)five `CN^(-)` and one `NOS^(-)`=6
(ii)Iron is in +2 oxidation state and atomic number of iron is 26.
Therefore, EAN=24+12=36
(iii)`Fe^(2+)=3d^(5)4s^(0)`

`CN^-` is strong field ligand which compels for paring of electron. Therefore , there is one unpaired electron.
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