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In how many of the following reactions o...

In how many of the following reactions one of the products is obtained as a black precipitate ?
(i)`Bi(OH)_3 darr +[Sn(OH)_4]^(2-)(aq)to`Products
(ii)`Bi^(3+)(aq)+I^(-)(aq)("not in excess")to`Products
(iii)`Bi^(3+)(aq)+H_2S(g)overset(H^+)to`Products
(iv)`[Bil_4]^(-)(aq)+H_2O(l)overset("dilution")to`Products
(v)`Bi^(3+)(aq)+C_9H_7ON(5%)+H^(+)(aq)+I^(-)(6M)to` Products
(vi)`Bi^(3+)(aq)+C_6H_3(OH)_3(10%)to`Products
(vii)`BiO. OH darr + H_2O_2(aq)to` Products

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To determine how many of the given reactions produce a black precipitate, we will analyze each reaction step by step. ### Step 1: Analyze the Reactions 1. **Reaction (i)**: \[ \text{Bi(OH)}_3 + \text{[Sn(OH)}_4]^{2-} \rightarrow \text{Products} \] - The products are Bi and Sn(OH)6^{2-}. - **Black Precipitate**: Yes, Bi is a black precipitate. 2. **Reaction (ii)**: \[ \text{Bi}^{3+} + \text{I}^- \rightarrow \text{Products} \] - The product is BiI3. - **Black Precipitate**: Yes, BiI3 is a black precipitate. 3. **Reaction (iii)**: \[ \text{Bi}^{3+} + \text{H}_2\text{S} \rightarrow \text{Products} \] - The product is Bi2S3. - **Black Precipitate**: Yes, Bi2S3 is a black precipitate. 4. **Reaction (iv)**: \[ \text{[BiI}_4]^{-} + \text{H}_2\text{O} \rightarrow \text{Products} \] - The product is Bi3 and I^-. - **Black Precipitate**: Yes, Bi3 is a black precipitate. 5. **Reaction (v)**: \[ \text{Bi}^{3+} + \text{C}_9\text{H}_7\text{ON} + \text{H}^+ + \text{I}^- \rightarrow \text{Products} \] - The product is a complex, C9H7ON·HBi4. - **Black Precipitate**: No, this is a red precipitate. 6. **Reaction (vi)**: \[ \text{Bi}^{3+} + \text{C}_6\text{H}_3(\text{OH})_3 \rightarrow \text{Products} \] - The product is Bi(C6H3O3)3. - **Black Precipitate**: No, this is a yellow precipitate. 7. **Reaction (vii)**: \[ \text{BiO.OH} + \text{H}_2\text{O}_2 \rightarrow \text{Products} \] - The product is BiO3^{-}. - **Black Precipitate**: No, this is a yellowish-brown precipitate. ### Step 2: Count the Reactions Producing Black Precipitates From the analysis: - Reactions (i), (ii), (iii), and (iv) produce black precipitates. - Reactions (v), (vi), and (vii) do not produce black precipitates. ### Conclusion **Total Reactions Producing Black Precipitate**: 4

To determine how many of the given reactions produce a black precipitate, we will analyze each reaction step by step. ### Step 1: Analyze the Reactions 1. **Reaction (i)**: \[ \text{Bi(OH)}_3 + \text{[Sn(OH)}_4]^{2-} \rightarrow \text{Products} \] ...
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