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CH2=CH-CH2OHundersetIoverset(PhH//HF)toA...

`CH_2=CH-CH_2OHundersetIoverset(PhH//HF)toAunderset(II)overset(H_2//Pt)toBunderset(III)overset(NBS)toCunderset(IV)overset(H_2O,"acetone")toDundersetVoverset(MnO_2)toE`
Which of the following statement is/are correct ?

A

B' gives total 5 monochloro products on photochemical chlorination

B

E' gives positive test with NaOH

C

D' gives instant turbilty with HCl + `ZnCl_2`

D

`1^(st)` step is an electrophilic substitution reaction

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The correct Answer is:
To solve the given problem, we need to analyze the series of reactions step by step and identify the products formed at each stage. Let's break it down: ### Step 1: Identify Product A The starting compound is **CH₂=CH-CH₂OH** (an allylic alcohol). This compound reacts with **PhH** (benzene) in the presence of **HF**. - The hydroxyl group (OH) is substituted by the phenyl group (Ph), resulting in: **A = CH₂=CH-CH₂Ph** ### Step 2: Identify Product B Next, product A undergoes reduction with **H₂** in the presence of **Pt** (platinum catalyst). - The double bond is reduced, leading to: **B = CH₃-CH₂-CH₂Ph** ### Step 3: Identify Product C Product B reacts with **NBS** (N-bromosuccinimide). The bromine atom will add to the most stable carbocation formed during the reaction. - The bromine will add to the carbon adjacent to the phenyl group, forming: **C = CH₃-CH(Br)-CH₂Ph** ### Step 4: Identify Product D Product C reacts with **H₂O** in the presence of **acetone**. This reaction will lead to the substitution of the bromine atom with a hydroxyl group (OH). - The resulting product will be: **D = CH₃-CH(OH)-CH₂Ph** ### Step 5: Identify Product E Finally, product D undergoes oxidation with **MnO₂**. This will convert the secondary alcohol to a ketone. - The final product will be: **E = CH₃-CO-CH₂Ph** ### Summary of Products - **A = CH₂=CH-CH₂Ph** - **B = CH₃-CH₂-CH₂Ph** - **C = CH₃-CH(Br)-CH₂Ph** - **D = CH₃-CH(OH)-CH₂Ph** - **E = CH₃-CO-CH₂Ph** ### Analyzing Statements Now, let's evaluate the statements based on the products derived: 1. **Statement A**: B gives a total of five monochloroproducts on photochemical chlorination. - **Correct**: B has five possible sites for chlorination, leading to five products. 2. **Statement B**: E gives a positive test with NaOH. - **Incorrect**: E is a ketone and does not give a positive test with NaOH. 3. **Statement C**: D gives instant turbidity with HCl and ZnCl₂. - **Correct**: D is a secondary alcohol and will give a positive test with the Lucas reagent (HCl and ZnCl₂). 4. **Statement D**: The first step is an electrophilic substitution reaction. - **Correct**: The first reaction involves the electrophilic substitution of the hydroxyl group with a phenyl group. ### Conclusion The correct statements are A, C, and D.

To solve the given problem, we need to analyze the series of reactions step by step and identify the products formed at each stage. Let's break it down: ### Step 1: Identify Product A The starting compound is **CH₂=CH-CH₂OH** (an allylic alcohol). This compound reacts with **PhH** (benzene) in the presence of **HF**. - The hydroxyl group (OH) is substituted by the phenyl group (Ph), resulting in: **A = CH₂=CH-CH₂Ph** ...
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