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Calculate the weight of lime (CaO) obtai...

Calculate the weight of lime (CaO) obtained by heating 290kg of 95% pure lime stone (`CaCO_3`).
`CaCO_3​→CaO+CO_2` ​

A

185Kg

B

158Kg

C

154Kg

D

198Kg

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the weight of lime (CaO) obtained by heating 290 kg of 95% pure limestone (CaCO₃), we will follow these steps: ### Step 1: Calculate the amount of pure limestone (CaCO₃) Given that the limestone is 95% pure, we can calculate the amount of pure CaCO₃ in the 290 kg sample. \[ \text{Amount of pure CaCO}_3 = \left(\frac{95}{100}\right) \times 290 \text{ kg} = 275.5 \text{ kg} \] ### Step 2: Convert the amount of pure CaCO₃ to grams To work with molar masses, we will convert kilograms to grams. \[ \text{Amount of pure CaCO}_3 = 275.5 \text{ kg} \times 1000 \text{ g/kg} = 275500 \text{ g} \] ### Step 3: Write the balanced chemical equation The decomposition of calcium carbonate (CaCO₃) can be represented by the following equation: \[ \text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2 \] ### Step 4: Determine the molar masses The molar mass of CaCO₃ is approximately 100 g/mol, and the molar mass of CaO is approximately 56 g/mol. ### Step 5: Calculate the amount of CaO produced From the balanced equation, we see that 1 mole of CaCO₃ produces 1 mole of CaO. Therefore, we can set up a proportion based on the molar masses: \[ \text{Weight of CaO} = \left(\frac{\text{Molar mass of CaO}}{\text{Molar mass of CaCO}_3}\right) \times \text{mass of pure CaCO}_3 \] Substituting the known values: \[ \text{Weight of CaO} = \left(\frac{56 \text{ g}}{100 \text{ g}}\right) \times 275500 \text{ g} \] ### Step 6: Perform the calculation Calculating the weight of CaO: \[ \text{Weight of CaO} = 0.56 \times 275500 \text{ g} = 154280 \text{ g} \] ### Step 7: Convert grams back to kilograms To express the weight of CaO in kilograms: \[ \text{Weight of CaO} = \frac{154280 \text{ g}}{1000 \text{ g/kg}} = 154.28 \text{ kg} \] ### Final Answer The weight of lime (CaO) obtained by heating 290 kg of 95% pure limestone is approximately **154.28 kg**. ---

To solve the problem of calculating the weight of lime (CaO) obtained by heating 290 kg of 95% pure limestone (CaCO₃), we will follow these steps: ### Step 1: Calculate the amount of pure limestone (CaCO₃) Given that the limestone is 95% pure, we can calculate the amount of pure CaCO₃ in the 290 kg sample. \[ \text{Amount of pure CaCO}_3 = \left(\frac{95}{100}\right) \times 290 \text{ kg} = 275.5 \text{ kg} \] ...
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