`x g` of `H_2O_2` requires `100mL` of `M//5 KMnO_4` in a titration in a solution having `pOH = 1.0` Which of the following is`//`are correct?

Options

A. The value of x is 1.7 g
B. The value of x is 0.34 g
C. `MnO_4^-` changes to `MnO_4^(-2)`
D. `H_2O_2` change to `O_2`

Answer

B,C,D

Explanation

pOH=1 strong basic medium
`implies MnO_4^(-)toMnO_4^(-2) (n=1)`
`2OH^(-)+H_2O_2 to O_2+2H_2O+2e^(-)`
meq. of `H_2O_2` = meq of `MnO_4^(-)`
`(x/34)/2xx1000=100xx1/5xx1 implies x=0.34 g`