Home
Class 12
PHYSICS
For a particle performing SHM, equation ...

For a particle performing `SHM`, equation of motion is given as `(d^(2))/(dt^(2)) + 4x = 0`. Find the time period

Text Solution

AI Generated Solution

To solve the problem, we start with the given equation of motion for a particle performing Simple Harmonic Motion (SHM): \[ \frac{d^2x}{dt^2} + 4x = 0 \] ### Step 1: Identify the form of the equation The equation can be rewritten in the standard form of SHM: ...
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    RESONANCE ENGLISH|Exercise Solved Miscellaneous Problems|9 Videos

  • SIMPLE HARMONIC MOTION

    RESONANCE ENGLISH|Exercise Board Level Exercise|24 Videos

  • SEMICONDUCTORS

    RESONANCE ENGLISH|Exercise Exercise 3|88 Videos

  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PHYSICS|784 Videos

Similar Questions

Explore conceptually related problems

For a particle performing SHM , equation of motion is given as (d^(2))/(dt^(2)) + 9x = 0 . Find the time period

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The time period of osciallation is given by

In a certain oscillatory system (particle is performing SHM), the amplitude of motion is 5 m and the time period is 4 s. the minimum time taken by the particle for passing betweens points, which are at distances of 4 m and 3 m from the centre and on the same side of it will approximately be

In a certain oscillatory system (particle is performing SHM), the amplitude of motion is 5 m and the time period is 4 s. the minimum time taken by the particle for passing betweens points, which are at distances of 4 m and 3 m from the centre and on the same side of it will approximately be

Equation of motion for a particle performing damped harmonic oscillation is given as x=e^(-0.1t) cos(10pit+phi) . The time when amplitude will half of the initial is :

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

Acceleration of a particle in SHM at displacement x=10 cm (from the mean position is a =-2.5 cm//s^(2) ). Find time period of oscillations.

A particle of mass 2 kg is moving of a straight line under the action of force F = (8 - 2x)N . It is released at rest from x = 6m . a. Is the particle moving simple harmonically. b. Find the equilibrium position of the particle. c. Write the equation of motion of the particle. d. Find the time period of SHM.