Home
Class 12
PHYSICS
A particle of mass 200 g executes a simp...

A particle of mass `200 g` executes a simple harmonic motion. The restoring force is provided by a spring of spring constant `80 N//m`. Find the time period.

Text Solution

Verified by Experts

`T = 12pi sqrt((m)/(k)) = 2pi sqrt((200 xx 10^(-3)kg)/(80 N//m)) = 2pi xx 0.05 s = 0.31 s`.
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    RESONANCE ENGLISH|Exercise Solved Miscellaneous Problems|9 Videos

  • SIMPLE HARMONIC MOTION

    RESONANCE ENGLISH|Exercise Board Level Exercise|24 Videos

  • SEMICONDUCTORS

    RESONANCE ENGLISH|Exercise Exercise 3|88 Videos

  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PHYSICS|784 Videos

Similar Questions

Explore conceptually related problems

A paricle of mass 30 kg executes a simple harmonic motion. The restorting force is provided by a spring of spring constant 80 N//m . Find the time period.

A particle of mass 200 g executes a simpel harmonit motion. The resrtoring force is provided by a spring of spring constant 80 N m^-1 . Find the time period.

A particle executes simple harmonic motion under the restoring force provided by a spring. The time period is T. If the spring is divided in two equal parts and one part is used to continue the simple harmonic motion, the time period will

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Find the maximum force exerted by the spring on the block.

A particle moving along the X-axis executes simple harmonic motion, then the force acting on it is given by where, A and K are positive constants.

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.

A 1kg block is executing simple harmonic motion of amplitude 0.1m on a smooth horizontal surface under the restoring force of a spring of spring constant 100 N//m . A block of mass 3 kg is gently placed on it at the instant it passes through the mean position. Assuming that the two blocks move together. Find the frequency and the amplitude of the motion.

A particle executing simple harmonic motion with an amplitude A. The distance travelled by the particle in one time period is

A horizontal spring block system of mass M executes simple harmonic motion. When the block is passing through its equilibrium position, an object of mass m is put on it and the two move together. Find the new amplitude and frequency of vibration. Given, k is the spring constant of the system.