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Block of mass m(2) is in equilibrium as ...

Block of mass `m_(2)` is in equilibrium as shown in figure. Anotherblock of mass `m_(1)` is kept gently on `m_(2)`. Find the time period of oscillation and amplitude.

Text Solution

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Time period `T = 2pisqrt((m_(1) + m_(2))/(K))`
At initial position since velocity is zero
it is the extreme position.
Amplitude `A = (m_(1)g)/(K)`
Ans. `T = 2pisqrt((m_(1) + m_(2))/(K))` Amplitude `= (m_(1)g)/(K)`
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