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A simple pendulum has some time period T...

A simple pendulum has some time period `T`. What will be the percentage change in its time period if its amplitude is decreased by `5%`

A

`6 %`

B

`3 %`

C

`1.5 %`

D

`0 %`

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The correct Answer is:
To solve the problem, we need to analyze how the time period of a simple pendulum is affected by changes in amplitude. ### Step-by-Step Solution: 1. **Understanding the Time Period of a Simple Pendulum**: The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] where: - \( L \) is the length of the pendulum, - \( g \) is the acceleration due to gravity. 2. **Identifying the Role of Amplitude**: In the formula for the time period, we can see that there is no term for amplitude. This indicates that the time period of a simple pendulum is independent of the amplitude of oscillation, as long as the amplitude is small. 3. **Considering the Change in Amplitude**: The problem states that the amplitude is decreased by 5%. However, since the time period does not depend on amplitude, this change will not affect the time period. 4. **Calculating the Percentage Change in Time Period**: Since the time period remains unchanged regardless of the change in amplitude, the percentage change in the time period can be calculated as: \[ \text{Percentage Change} = \frac{\text{Change in Time Period}}{\text{Original Time Period}} \times 100\% \] Since the change in time period is 0 (it remains the same), we have: \[ \text{Percentage Change} = \frac{0}{T} \times 100\% = 0\% \] 5. **Conclusion**: Therefore, the percentage change in the time period when the amplitude is decreased by 5% is **0%**. ### Final Answer: The percentage change in the time period is **0%**.

To solve the problem, we need to analyze how the time period of a simple pendulum is affected by changes in amplitude. ### Step-by-Step Solution: 1. **Understanding the Time Period of a Simple Pendulum**: The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} ...
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