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A mass M, attached to a horizontal sprin...

A mass M, attached to a horizontal spring, executes SHM with amplitude When the mass M passes through its mean position then a smaller mass m is placed over it and both of them move together with amplitude` A_(2)` The ratio of` (A_(1)/A_(2))` is :

A

`(M)/(M + m)`

B

`(M + m)/(M)`

C

`((M)/(M + m))^(1//2)`

D

`((M + m)/(M))^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`C.O.L.M.`
`MV_(max) = (m + M)V_("new") , V_(max) = A_(1)omega_(1)`
`V_("new") = (MV_(max))/((m + M))`
Now, `V_("new") = A_(2).omega_(2)`
`(MA_(1))/((m + M))sqrt((K)/(M)) = A_(2)sqrt((K)/((m + M)))`
`A_(2) = A_(1)sqrt((M)/((m + M))), (A_(1))/(A_(2)) = ((m + M)/(M))^(1//2)`
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