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A string fixed at both ends is 8.40 m lo...

A string fixed at both ends is `8.40 m` long and has a mass of `0.120 kg`. It is subjected to a tension of `96.0 N` and set oscillating. (a) What is the speed of the waves on the string? (b) What is the longest possible wavelength for a standing wave ? (c) Give the frequency of the wave.

Text Solution

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The correct Answer is:
(a) `82.0 m//s` , (b) `16.8 m` , (c) `4.88 Hz`.
(a) `V = sqrt((T)/(mu)) = sqrt((96)/(((0.12)/(8.4)))) = 82 m//sec`.
(b) for lowest possible wavelength ,
`(lambda)/(2) = l`
`lambda = 2l = 2 xx 8.4 = 16.8 m`
(c) `V = flambda = (v)/(lambda) = (82)/(16.8) = 4.38 Hz`.
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