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A transverse wave of amplitude 0.5 m and...

A transverse wave of amplitude `0.5 m` and wavelength 1 m and frequency 2 Hz is propagating in a string in the negative x - direction. The expression for this wave is [

A

`y(x,t) = 0.5 sin (2pix + 4pit)`

B

`y(x,t) = 0.5 cos (2pix - 4pit)`

C

`y(x,t) = 0.5 sin (pix - 2pit)`

D

`y(x,t) = 0.5 cos (2pix - 2pit)`

Text Solution

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The correct Answer is:
To find the expression for the transverse wave propagating in a string, we will follow these steps: ### Step 1: Identify the parameters of the wave We are given: - Amplitude (A) = 0.5 m - Wavelength (λ) = 1 m - Frequency (f) = 2 Hz ### Step 2: Calculate the angular frequency (ω) The angular frequency (ω) can be calculated using the formula: \[ \omega = 2\pi f \] Substituting the value of frequency: \[ \omega = 2\pi \times 2 = 4\pi \text{ rad/s} \] ### Step 3: Calculate the wave number (k) The wave number (k) is given by the formula: \[ k = \frac{2\pi}{\lambda} \] Substituting the value of wavelength: \[ k = \frac{2\pi}{1} = 2\pi \text{ rad/m} \] ### Step 4: Write the general wave equation The general wave equation for a wave traveling in the positive x-direction is: \[ y(x, t) = A \sin(kx - \omega t) \] Since the wave is traveling in the negative x-direction, we modify the equation to: \[ y(x, t) = A \sin(kx + \omega t) \] ### Step 5: Substitute the values into the wave equation Now we substitute the values of A, k, and ω into the equation: \[ y(x, t) = 0.5 \sin(2\pi x + 4\pi t) \] ### Final Expression Thus, the expression for the wave is: \[ y(x, t) = 0.5 \sin(2\pi x + 4\pi t) \] ---
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RESONANCE ENGLISH-WAVE ON STRING -Exercise- 1 PART II
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