A uniform rope of length 12 mm and mass 6 kg hangs vertically from a rigid support. A block of mass 2 kg is attached to the free end of the rope. A transverse pulse of wavelength 0.06 m is produced at the lower end of the rope. What is the wavelength of the pulse when it reaches the top of the rope?

Answer

2

Explanation

`f = ((f)/(lambda))` at lowest point
`f = (1)/(lambda)sqrt((mg)/(mu))`
`f^(1) = (v^(1))/(lambda^(1))` at highest point
`f^(1) = (1)/(lambda^(1)) sqrt(((M + m)g)/(mu))`
`f^(1) = f :` no any change in source frq.
`(1)/(lambda) sqrt((mg)/(mu)) = (1)/(lambda), sqrt(((M + m)g)/(mu)) rArr [lambda' = lambdasqrt((M + m)/(m))]`