An object of height 1mm is placed inside a sphere of refractive index `mu=2` and radius of curvature 20 cm as shown in the figure. Find the position, size, and nature of image, for the situation shown in Figure. Draw ray diagram.

Explanation

For refraction near point`A, U = -30, R = -20, n_(1) = 2 , n_(2) = 1`
Applying refraction formula
`(n_(2))/(v) - (m_(1))/(u) = (n_(2) - n_(1))/(R)`
`(1)/(V) - (2)/(-30) = (1-2)/(-20)`
`v = -60 cm`
`m = (h_(2))/(h_(1)) = (n_(1)v)/(n_(2)u) = (2(-60))/(1(-30)) = 4, :. h_(2) = 4mm`